No, React.lazy does not support named exports directly.
React.lazy expects the module you are importing to have a default export. If your module only has named exports, React.lazy will not work out of the box and you will encounter an error.

Here's why:
When you use React.lazy, React expects the module to resolve to a component through a default export. Named exports are not automatically understood by React.lazy.

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Example of correct usage (default export):

// MyComponent.js
export default function MyComponent() {
  return <div>Hello from MyComponent</div>;
}

// App.js
import React, { Suspense } from 'react';

const MyComponent = React.lazy(() => import('./MyComponent'));

function App() {
  return (
    <Suspense fallback={<div>Loading...</div>}>
      <MyComponent />
    </Suspense>
  );
}

export default App;

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What if you only have named exports?
If the module exports components by name, you have two options:

1. Re-export with a default: Modify the module to add a default export.

// MyComponent.js
export function MyComponent() {
  return <div>Hello from MyComponent</div>;
}

// Add this line
export default MyComponent;

2. Use a wrapper inside React.lazy: If you can't modify the original module, you can dynamically import the named export and re-export it as default inline:

const MyComponent = React.lazy(() =>
  import('./MyComponent').then(module => ({ default: module.MyComponent }))
);

In this way, you manually tell React.lazy which named export to treat as the default export.

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Summary:

• React.lazy requires a default export.
• If your module only has named exports, either add a default export or map the named export to a default manually during dynamic import.

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